Leet Code | MySQL | 1179. Reformat Department Table

1179. Reformat Department Table

https://leetcode.com/problems/reformat-department-table/

Reformat Department Table - LeetCode

Write an SQL query to reformat the table such that there is a department id column and a revenue column for each month.

 

SELECT id
, SUM(CASE WHEN month = 'Jan' THEN revenue ELSE NULL END) AS Jan_Revenue
, SUM(CASE WHEN month = 'Feb' THEN revenue ELSE NULL END) AS Feb_Revenue
, SUM(CASE WHEN month = 'Mar' THEN revenue ELSE NULL END) AS Mar_Revenue
, SUM(CASE WHEN month = 'Apr' THEN revenue ELSE NULL END) AS Apr_Revenue
, SUM(CASE WHEN month = 'May' THEN revenue ELSE NULL END) AS May_Revenue
, SUM(CASE WHEN month = 'Jun' THEN revenue ELSE NULL END) AS Jun_Revenue
, SUM(CASE WHEN month = 'Jul' THEN revenue ELSE NULL END) AS Jul_Revenue
, SUM(CASE WHEN month = 'Aug' THEN revenue ELSE NULL END) AS Aug_Revenue
, SUM(CASE WHEN month = 'Sep' THEN revenue ELSE NULL END) AS Sep_Revenue
, SUM(CASE WHEN month = 'Oct' THEN revenue ELSE NULL END) AS Oct_Revenue
, SUM(CASE WHEN month = 'Nov' THEN revenue ELSE NULL END) AS Nov_Revenue
, SUM(CASE WHEN month = 'Dec' THEN revenue ELSE NULL END) AS Dec_Revenue
FROM Department
GROUP BY id

/*
{"headers": ["id", "revenue", "month"], 
"values": [[1, 8000, "Jan"], [2, 9000, "Jan"], 
[3, 10000, "Feb"], [1, 7000, "Feb"], [1, 6000, "Mar"]]}
*/